How many grams of water (H2O , GFW = 18.02 g/mol) will be produced when 35.8 grams of calcium hydroxide (Ca(OH),

„GFW = 74.10 g/mol) reacts with hydrochloric acid?

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Answer :

vtamit3 vtamit3 · Answer 1 · 2025-04-04T12:27:54-04:00

17.42 grams of water (H₂O) will be produced when 35.8 grams of calcium hydroxide (Ca(OH)₂) reacts with hydrochloric acid.

Given,

Mass of calcium hydroxide (Ca(OH)₂) = 35.8 grams

Molar mass of calcium hydroxide (Ca(OH)₂) = 74.10 g/mol

Molar mass of water (H₂O) = 18.02 g/mol

The balanced equation for the reaction between calcium hydroxide and hydrochloric acid is: Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

For every 1 mole of calcium hydroxide that reacts, 2 moles of water are produced.

Moles = Mass / Molar mass

Moles of Ca(OH)₂ = 35.8/ 74.10 ≈ 0.483 mol

Moles of H₂O = 2 × Moles of Ca(OH)₂ = 2 × 0.483 = 0.966 mol

Mass = Moles × Molar mass

Mass of H₂O = 0.966 × 18.02 ≈ 17.42

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