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Answer :
We begin by noting that the cylinder has a diameter of 4 feet and a height of 5 feet. The weight density of aluminum is given as 165 pounds per cubic foot.
1. First, find the radius of the cylinder. Since the diameter is 4 feet:
[tex]$$
r = \frac{4}{2} = 2 \text{ feet}
$$[/tex]
2. Next, compute the volume of the cylinder using the formula for the volume of a cylinder:
[tex]$$
V = \pi r^2 h
$$[/tex]
Using an approximate value for [tex]$\pi$[/tex] as 3.14, we substitute the values:
[tex]$$
V = 3.14 \times (2^2) \times 5 = 3.14 \times 4 \times 5 = 3.14 \times 20 = 62.8 \text{ cubic feet}
$$[/tex]
3. Finally, calculate the weight of the cylinder by multiplying the volume by the density of aluminum:
[tex]$$
\text{Weight} = V \times \text{density} = 62.8 \times 165 = 10362 \text{ pounds}
$$[/tex]
Thus, the weight of the cylinder is 10,362 pounds.
The best answer is:
D) 10,362 lbs.
1. First, find the radius of the cylinder. Since the diameter is 4 feet:
[tex]$$
r = \frac{4}{2} = 2 \text{ feet}
$$[/tex]
2. Next, compute the volume of the cylinder using the formula for the volume of a cylinder:
[tex]$$
V = \pi r^2 h
$$[/tex]
Using an approximate value for [tex]$\pi$[/tex] as 3.14, we substitute the values:
[tex]$$
V = 3.14 \times (2^2) \times 5 = 3.14 \times 4 \times 5 = 3.14 \times 20 = 62.8 \text{ cubic feet}
$$[/tex]
3. Finally, calculate the weight of the cylinder by multiplying the volume by the density of aluminum:
[tex]$$
\text{Weight} = V \times \text{density} = 62.8 \times 165 = 10362 \text{ pounds}
$$[/tex]
Thus, the weight of the cylinder is 10,362 pounds.
The best answer is:
D) 10,362 lbs.
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