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Answer :
Assuming ideal behavior of the gas for a fixed amount when temperature is held constant, the pressure and volume are inversely proportional as given by the expression
P1V1 = P2V2
where the terms with subscripts of one represent the initial conditions for pressure and volume of the gas while for terms with subscripts of two represent the final conditions.
Rearranging the Boyle's law equation to calculate for the final volume V2:
V2 = P1V1 / P2
V2 = (99.7 kPa)(150 mL) / 99.8 kPa
V2 = 149.85 mL
P1V1 = P2V2
where the terms with subscripts of one represent the initial conditions for pressure and volume of the gas while for terms with subscripts of two represent the final conditions.
Rearranging the Boyle's law equation to calculate for the final volume V2:
V2 = P1V1 / P2
V2 = (99.7 kPa)(150 mL) / 99.8 kPa
V2 = 149.85 mL
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Rewritten by : Barada
The student's question concerns the calculation of the final volume of a gas when the pressure changes, following Boyle's Law, which is a concept in physics.Upon calculation the final volume would be 149.85 mL
The question is referring to the behavior of gases under different pressures and volumes, which is described by Boyle's Law in physics. If we have a pressure system that begins at 99.7 kPa with a volume of 150 mL and the pressure changes to 99.8 kPa, we can use Boyle's Law to find the final volume. Boyle's Law states that for a given mass of an ideal gas at constant temperature, the product of pressure and volume is a constant (P1V1 = P2V2).
However, there might be a typo in this question as the final pressure is given as 99.8 kPa, which is higher than the initial pressure, implying that the volume should decrease, contrary to the statement which mentions a drop in pressure. If we consider that the pressure actually drops to 99.8 kPa, the final volume can be calculated using the formula:
V2 = (P1 * V1) / P2
Where V1 is the initial volume, P1 is the initial pressure, and P2 is the final pressure. Substituting the values we give:
V2 = (99.7 kPa * 150 mL) / 99.8 kPa=149.85 mL
The final volume, V2, would then be slightly larger than the initial volume due to the decrease in pressure .
