Answer :

Final answer:

Approximately 35.46 grams of oxygen are contained in 135 grams of isopropyl alcohol, calculated by setting up a proportion based on combustion analysis data.

Explanation:

To calculate the mass of oxygen in 135 grams of isopropyl alcohol, we need to look at the combustion analysis data given.

If we combust 0.255 grams of isopropyl alcohol, it results in 0.154 grams of carbon (C) and 0.034 grams of hydrogen (H), totaling 0.188 grams together.

Therefore, the 'missing' mass in the combusted isopropyl alcohol is due to the oxygen (O) atoms:

0.255 grams (initial mass of isopropyl alcohol) - 0.188 grams (C + H) = 0.067 grams (O)

This means in the initial 0.255 grams of isopropyl alcohol, 0.067 grams are oxygen. To find out how many grams of oxygen are in 135 grams of isopropyl alcohol, we set up a proportion:

(0.067 grams O / 0.255 grams isopropyl alcohol) = (x grams O / 135 grams isopropyl alcohol)

Cross-multiplying and solving for x, we calculate the mass of oxygen in 135 grams of isopropyl alcohol:

x = (0.067 grams O / 0.255 grams isopropyl alcohol) × 135 grams isopropyl alcohol

x = 35.46 grams O (rounded to two decimal places)

So, there are approximately 35.46 grams of oxygen in 135 grams of isopropyl alcohol.

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