High School

We appreciate your visit to A 65 kg sprinter exerts a force of 798 N at a 19 angle What is the horizontal component of the force A 185 N. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A 65 kg sprinter exerts a force of 798 N at a 19° angle. What is the horizontal component of the force?

A. 185 N
B. 752 N
C. 775 N
D. 798 N

Answer :

Final answer:

The horizontal component of the force exerted by the 65 kg sprinter, who applies a force at a 19° angle, is approximately 752 N, calculated by multiplying the total force by the cosine of the angle.

Explanation:

To find the horizontal component of the force exerted by the 65 kg sprinter, we use the cosine function of trigonometry since the force is at a 19° angle to the horizontal. The horizontal component Fh can be calculated using:

Fh = F × cos(θ)

Where:

  • F is the total force exerted by the sprinter (798 N).
  • θ is the angle of the force concerning the horizontal plane (19°).

Plugging the values into the equation, we get:

Fh = 798 N × cos(19°)

Calculating the cosine of 19 degrees and then multiplying by the force, the horizontal component comes out to be:

Fh ≈ 798 N × 0.945 = 754.11 N

Therefore, the closest option to our calculated value is (b) 752 N.

Learn more about the Horizontal Component of Force here:

https://brainly.com/question/32869433

#SPJ11

Thanks for taking the time to read A 65 kg sprinter exerts a force of 798 N at a 19 angle What is the horizontal component of the force A 185 N. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada