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Answer :
The equation of a line in Slope-Intercept form is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
Given this equation:
[tex]y=4x+2[/tex]You can see that:
[tex]\begin{gathered} m=4 \\ b=2 \end{gathered}[/tex]Since "x" is zero when the line cuts the y-axis, you have this point:
[tex](0,2)[/tex]The value of "y" is zero when the line cuts the x-axis, so you must substitute that value into the equation and solve for "x" in order to find the x-intercept:
[tex]\begin{gathered} 0=4x+2 \\ -2=4x \\ \frac{-2}{4}=x \\ x=-\frac{1}{2} \\ x=-0.5 \end{gathered}[/tex]So you also have this point:
[tex](-0.5,0)[/tex]Plot the points on the Coordinate plane and graph the line:
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