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Answer :
To find the total number of batters Quinton struck out in all three baseball games, you add the strikeouts from each game: 12 + 5 + 8, which equals 25. Quinton struck out a total of 25 batters.
The number of batters Quinton struck out in all three baseball games can be found by adding the number of strikeouts from each game together. He struck out 12 batters in the first game, 5 batters in the second game, and 8 batters in the third game. The total is calculated as follows:
First game strikeouts: 12
Second game strikeouts: 5
Third game strikeouts: 8
Adding these numbers together gives us:
12 + 5 + 8 = 25.
Therefore, Quinton struck out a total of 25 batters in all three games.
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Rewritten by : Barada
We know that Quinton struck out 12 batters, 5 batters, and 8 batters. Key word: in all. In all means addition. So, 12 + 5= 17, and 17 + 8= 25. 25 batters.
