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(a) Two point charges totaling [tex]8.00 \, \mu C[/tex] exert a repulsive force of [tex]0.150 \, N[/tex] on one another when separated by [tex]0.500 \, m[/tex]. What is the charge on each?

A. [tex]4.00 \, \mu C[/tex]
B. [tex]2.00 \, \mu C[/tex]
C. [tex]6.00 \, \mu C[/tex]
D. [tex]8.00 \, \mu C[/tex]

Answer :

Final answer:

To find the charge on each point, we can use Coulomb's Law formula. The charge on each point is 4.00 µC.

Explanation:

To find the charge on each point, we can use Coulomb's Law formula, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Let the charges of the two point charges be q1 and q2. We are given that q1 + q2 = 8.00 µC and the force between them is 0.150 N. The distance between them is 0.500 m.

Using the formula, we can express the force as:

F = k * (q1 * q2) / r2

where k is the electrostatic constant and has a value of 8.99 x 109 N m2/C2. Solving for q1 and q2, we find that q1 = q2 = 4.00 µC. Therefore, the charge on each point is 4.00 µC.

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