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Given that the specific heat of chromium is [tex]0.455 \, \text{J/g} \cdot \text{K}[/tex], find the final temperature after [tex]35.9 \, \text{J}[/tex] of energy is removed from [tex]11.7 \, \text{g}[/tex] of chromium at [tex]28.5^\circ \text{C}[/tex].

Answer :

Final answer:

The final temperature of chromium after 35.9J of energy is removed will be approximately 21.8°C. This is calculated by subtracting the change in temperature (ΔT) from the initial temperature.

Explanation:

The principal concept in the question involves the concept of specific heat capacity in the field of thermodynamics. The formula used is q = mcΔT , where q is the heat transferred, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature. In this case, you are given q, m, and c, and you are solving for ΔT.

From the values given in the question, 35.9J is the heat energy to be removed (q) from 11.7g of chromium (m), whose specific heat capacity (c) is 0.455J/g∙K. The initial temperature is given as 28.5°C.

First, calculate ΔT which is q/(mc). So, ΔT = 35.9J / (11.7g × 0.455J/g∙K) ≅ 6.7°C. Now, you are asked to find the final temperature, which is obtained by subtracting ΔT (the change in temperature) from the initial temperature 28.5°C - 6.7°C ≅ 21.8°C.

Therefore, the final temperature of chromium after 35.9J of energy is removed will be approximately 21.8°C.

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