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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high?

(Formula: [tex]PE = mgh[/tex])

A. 75 J
B. 735 J
C. 245 J
D. 37.8 J

Answer :

To find the potential energy of a 25 kg bicycle resting at the top of a hill 3 meters high, you can use the formula for gravitational potential energy:

[tex]\[ PE = m \times g \times h \][/tex]

where:
- [tex]\( m \)[/tex] is the mass (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]),
- [tex]\( h \)[/tex] is the height (in meters).

Let's plug the values into the formula:

1. Identify the given values:
- Mass [tex]\( m = 25 \, \text{kg} \)[/tex]
- Acceleration due to gravity [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- Height [tex]\( h = 3 \, \text{m} \)[/tex]

2. Substitute these values into the formula:

[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]

3. Calculate step-by-step:
- First, calculate [tex]\( m \times g = 25 \times 9.8 = 245 \)[/tex]
- Then, multiply by the height: [tex]\( 245 \times 3 = 735 \)[/tex]

The potential energy of the bicycle is [tex]\( 735 \, \text{Joules (J)} \)[/tex].

Therefore, the correct answer is [tex]\( \boxed{735 \, J} \)[/tex].

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