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Answer :
Sure! Let's solve this step by step.
1. Identify the given values:
- The evaporating pressure for R-22 is 76 psig.
- The evaporator outlet temperature is 58°F.
2. Understand what we need to find:
- We need to find the evaporator superheat.
3. Define superheat:
- Superheat is the difference between the actual temperature at the evaporator outlet and the saturation temperature at the given pressure.
4. Determine the saturation temperature:
- For R-22 refrigerant, the saturation temperature corresponding to 76 psig is approximately 45°F. (This is a standard value known from pressure-temperature correlation tables used in HVAC/R).
5. Calculate the superheat:
- Superheat = Evaporator outlet temperature - Saturation temperature
- Superheat = 58°F - 45°F
6. Compute the result:
- Superheat = 13°F
So, the evaporator superheat is [tex]\( \boxed{13^\circ \text{F}} \)[/tex].
The correct answer is:
a. [tex]\( 13^\circ \text{F} \)[/tex]
1. Identify the given values:
- The evaporating pressure for R-22 is 76 psig.
- The evaporator outlet temperature is 58°F.
2. Understand what we need to find:
- We need to find the evaporator superheat.
3. Define superheat:
- Superheat is the difference between the actual temperature at the evaporator outlet and the saturation temperature at the given pressure.
4. Determine the saturation temperature:
- For R-22 refrigerant, the saturation temperature corresponding to 76 psig is approximately 45°F. (This is a standard value known from pressure-temperature correlation tables used in HVAC/R).
5. Calculate the superheat:
- Superheat = Evaporator outlet temperature - Saturation temperature
- Superheat = 58°F - 45°F
6. Compute the result:
- Superheat = 13°F
So, the evaporator superheat is [tex]\( \boxed{13^\circ \text{F}} \)[/tex].
The correct answer is:
a. [tex]\( 13^\circ \text{F} \)[/tex]
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