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Which line is perpendicular to a line that has a slope of [tex]$-\frac{5}{6}$[/tex]?

A. line JK
B. line LM
C. line NO
D. line PQ

Answer :

To find a line that is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex], we need to determine the negative reciprocal of this slope. Here's how you can do it:

1. Understand the Concept: For two lines to be perpendicular, the product of their slopes must be [tex]\(-1\)[/tex].

2. Find the Negative Reciprocal: The slope of the given line is [tex]\(-\frac{5}{6}\)[/tex]. The negative reciprocal of a fraction is obtained by flipping the fraction (swapping the numerator and the denominator) and then changing the sign.

3. Calculate the Negative Reciprocal:
- Flip [tex]\(-\frac{5}{6}\)[/tex] to get [tex]\(-\frac{6}{5}\)[/tex].
- Change the sign to get [tex]\(\frac{6}{5}\)[/tex].

So, the slope of the line that is perpendicular to a line with a slope of [tex]\(-\frac{5}{6}\)[/tex] is [tex]\(\frac{6}{5}\)[/tex].

Now, among the options provided (line JK, line LM, line NO, line PQ), you would look for the line that has a slope of [tex]\(\frac{6}{5}\)[/tex]. If additional information about these lines were provided, such as equations or points they pass through, you could use it to determine which line has this slope.

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