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Answer :
Final answer:
The energy efficiency of the kettle was calculated to be 41.3%. This is due to the fact that the kettle loses some of its energy to the environment as heat. Thus, the "missing" energy is the energy that is lost as heat to the surroundings.
Explanation:
To calculate the energy efficiency of the kettle, we first need to calculate the energy supplied to the kettle and the energy used by the kettle. The energy supplied to the kettle (E) is the power times the time, or 900W * 270 seconds = 243,000 joules.
To calculate the energy used by the kettle, we can use the formula Q = mcΔT, where m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. Here, m is 1 kg, c is 4.186 J/g°C, and ΔT is 24°C, thus Q = 1 kg * 4.186 J/g°C * 24°C = 100,464 J.
The energy efficiency of the kettle can then be calculated as (energy used / energy supplied) * 100% = (100,464 J / 243,000 J) * 100% = 41.3%. The reason the kettle is not 100% efficient is because some of the energy is lost as heat to the surrounding environment. Thus, the "missing" energy is expelled into the environment as wasted heat energy.
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