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If your laboratory conditions were 743.1 tort and the volume of your apparatus was 165.2 mL, calculate the molar mass of an unknown liquid that vaporizes at 99.7 °C and weighs 0.3386 g.

Answer :

The given mass is 0.3386 g, and we have calculated the number of moles. By dividing the mass by the moles, we can find the molar mass of the unknown liquid.

To calculate the molar mass of the unknown liquid, we can use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
First, we need to convert the given temperature of 99.7 °C to Kelvin. To do this, we add 273.15 to the Celsius temperature:
T = 99.7 + 273.15 = 372.85 K
Next, let's convert the volume from milliliters to liters:
V = 165.2 mL = 165.2/1000 L = 0.1652 L
Now, we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
We know the pressure (P) is 743.1 tort, but we need to convert it to atmospheres (atm) since the ideal gas constant (R) is in atm:
1 atm = 760 torr
P = 743.1 tort * (1 atm / 760 tort) = 0.9765 atm
Plugging in the values, we get:
n = (0.9765 atm * 0.1652 L) / (0.0821 L*atm/(mol*K) * 372.85 K)
Calculating this expression gives us the number of moles.
Next, we can calculate the molar mass (M) using the formula:
M = mass / moles
The given mass is 0.3386 g, and we have calculated the number of moles. By dividing the mass by the moles, we can find the molar mass of the unknown liquid.

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