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Answer :
Final answer:
To answer these questions, we use the normal distribution and R programming. We calculate z-scores to find probabilities and to determine cutoff points. We can use the 'qnorm' function in R to find values corresponding to specific percentiles. The z-score of 0.89 means the length of the stem is 0.09 standard deviations longer than the average rose stem.
Explanation:
To answer these questions, we can use the normal distribution. Let's break down each question:
a. To find the probability that a given rose stem will be shorter than 21.9 inches, we need to calculate the z-score and find the corresponding probability using R. The formula to calculate the z-score is:
z = (x - mean) / standard deviation
where x is the given value, mean is the mean length of rose stems, and standard deviation is the standard deviation of rose stem lengths. Using R, we can calculate the z-score and find the probability that a rose stem will be shorter than 21.9 inches.
b. To find the probability that a given rose will be considered a long stem rose (stem length > 24 inches), we follow a similar process as in part a. Calculate the z-score and find the probability.
c. To find the maximum stem length that qualifies to be used as a corsage, we need to find the value of x (stem length) that corresponds to the 6th percentile. We can use R to find this value by first calculating the z-score using the formula mentioned earlier, and then using the 'qnorm' function in R to find the corresponding value of x.
d. The z-score of 0.89 tells us that the length of this stem is 0.09 standard deviations longer than the average rose stem. So, the correct interpretation is option C.
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