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If \( y \) varies inversely with the square of \( x \), and \( y = 7 \) when \( x = 3 \), find \( y \) when \( x = 0.2 \).

A. 100.8
B. 8.4
C. 0.0049
D. 0.084

Answer :

Final answer:

The question revolves around the mathematical concept of inverse square variation. Utilizing the given information, the constant of variation is calculated as 63. The value of y for x equals 0.2 then comes out to be 1575, which does not match the provided choices.

Explanation:

The problem given is an example of inverse square variation - a type of mathematical relationship between two variables. In this case, y varies inversely with the square of x. The relationship can be represented by the equation y = k / x², where k is a fixed constant.

Using the information given, we can calculate the value of k when y = 7 and x = 3, to be k = y * x² = 7 * 3² = 63. Now, we find y when x = 0.2 by substituting these values into our equation. Thus, y = k / x² = 63 / (0.2)² = 1575. However, the actual values provided as options in the question do not match this result, potentially due to a discrepancy in the provided choices or a misunderstanding of the problem requirements.

Learn more about Inverse Square Variation here:

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