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The value of Kc for the following reaction is .070. What is the equilibrium concentration of C₄H₁₀ if the equilibrium concentrations of C₂H₆ and C₂H₄ are both 0.035M?

C₄H₁₀(g) ---> C₂H₆(g) + C₂H₄(g)

a. 0.018
b. 57
c. 0.50
d. 2.0
e. 1.0
f. No answer is found.

Answer :

Final answer:

After setting up the expression for Kc with the given equilibrium concentrations and solving for the unknown concentration, the equilibrium concentration of C4H10 is found to be 0.018M. The correct option a.

Explanation:

The value of Kc for the reaction C4H10(g) → C2H6(g) + C2H4(g) is given as 0.070. To find the equilibrium concentration of C4H10, we can set up the expression for Kc which is [C2H6][C2H4]/[C4H10]. Given that the equilibrium concentrations of C2H6 and C2H4 are both 0.035M, we substitute these into the Kc expression and solve for [C4H10].

Kc = [C2H6][C2H4]/[C4H10] → 0.070 = (0.035)(0.035)/[C4H10]. Solving for [C4H10] gives us 0.0175, or when rounded to two significant figures, 0.018M, which corresponds to option (a).

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