Answer :

Final answer:

To calculate the mass of solute in a solution, convert the concentration from ppm to mol/L. Then, use the volume of the solution and the molar mass of the solute to calculate the mass. In this case, in a 3.0 L solution with 36.9 ppm SnCl₂, the mass of solute would be 0.581 mg.

Explanation:

To calculate the mass of solute in a solution, we first need to convert the concentration from parts per million (ppm) to moles per liter (mol/L). Step 1 is to convert the concentration from ppm to a decimal form. For example, if a solution contains 36.9 ppm SnCl₂, it means there are 36.9 mg of SnCl₂ for every 1 L of solution. So, the concentration is 36.9 mg/L.

Step 2 is to convert the concentration from mg/L to mol/L. To do this, we need to know the molar mass of SnCl₂, which is 189.6 g/mol. We can convert 36.9 mg/L to g/L by dividing by 1000. Then, we can convert g/L to mol/L by dividing by the molar mass of SnCl₂.

So, in a 3.0 L solution that contains 36.9 ppm SnCl₂, the mass of solute (SnCl₂) would be (36.9 mg/L / 1000) g/L * (3.0 L) * (1 mol SnCl₂ / 189.6 g) * 1000 mg/g = 0.581 mg.

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