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Answer :
To determine if a weight of 110 pounds is unusual weight is if the absolute value of the z-score is greater than 2. Therefore, a z-score of -53.8 is extremely unusual. The correct answer is D) z = -53.8; unusual.
Explanation:
To determine whether the weight of 110 pounds is unusual, we need to calculate the z-score, which measures how many standard deviations the weight is away from the mean. The formula for z-score is z = (x - mean) / standard deviation. Plugging in the values, we get z = (110 - 164) / 25.6 = -53.8.
A commonly used criteria to determine if a value is unusual is if the absolute value of the z-score is greater than 2. Therefore, a z-score of -53.8 is extremely unusual. The correct answer is D) z = -53.8; unusual.
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The weight of 110 pounds is not considered unusual among a population with a mean weight of 164 pounds and a standard deviation of 25.6 pounds.
To determine whether the weight of 110 pounds is unusual among a population with a mean weight of 164 pounds and a standard deviation of 25.6 pounds, we need to calculate the z-score. The z-score formula is (value - mean)/standard deviation. Plugging in the values, we get a z-score of -2.1. Since the z-score falls within the range of -1.96 and 1.96, the weight of 110 pounds is not considered unusual. Therefore, the correct answer is B) z=-2.1; not unusual.
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