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A 7.70 kg rope is being pulled by a force of 48.5 N to the right and a force of 37.6 N to the left. What is the acceleration of the rope?

Answer :

The acceleration of the rope is 1.41688 m/s^2 to the right, calculated by applying Newton's second law with a net force of 10.9 N and the mass of the rope

To find the acceleration of the rope, we need to consider the net force acting on it and use Newton's second law of motion (F = ma). With a force of 48.5 N pulling to the right and a force of 37.6 N pulling to the left, the net force can be calculated as follows:

Net Force = Force to the right - Force to the left
Net Force = 48.5 N - 37.6 N = 10.9 N

Now, using Newton's second law:
Acceleration (a) = Net Force (F) / Mass (m)

Acceleration = 10.9 N / 7.70 kg
Acceleration = 1.41688 m/s2 (to the right)

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