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Answer :
Final answer:
To find which of the given numbers becomes a perfect cube when divided by 5, we need to calculate the cube root of each number and check if it is an integer. The only number that satisfies this condition is a. 125.
Explanation:
To determine which of the given numbers becomes a perfect cube when divided by 5, we need to find the cube root of each number and see if it is an integer. The cube root of a number is the number that, when raised to the power of 3, gives the original number. Dividing a number by 5 is the same as multiplying it by 5-1, so to find the cube root, we need to find the cube root of each number and check if it is a multiple of 5-1 or 1/5. Let's calculate:
- a) 125: The cube root of 125 is 5, which is a multiple of 1/5. Therefore, 125 becomes a perfect cube when divided by 5.
- b) 25: The cube root of 25 is not an integer. Therefore, 25 does not become a perfect cube when divided by 5.
- c) 625: The cube root of 625 is not an integer. Therefore, 625 does not become a perfect cube when divided by 5.
- d) 3125: The cube root of 3125 is not an integer. Therefore, 3125 does not become a perfect cube when divided by 5.
Therefore, the only number that becomes a perfect cube when divided by 5 is 125.
Learn more about Cube roots here:
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