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Answer :
Final answer:
To create the interleaved array with a gap of 4, we skip 4 positions each time starting from the first element. The first interleaved array obtained using this method is option a) [ 80, 54, 67, 83, 43, 17, 42, 18, 13 ].So the correct answer is a) [ 80, 54, 67, 83, 43, 17, 42, 18, 13 ].
Explanation:
The question requires us to create an interleaved array from the given array using a gap value of 4. To do this, we start with the first element and then skip 4 positions to select the next element, continuing this pattern until we reach the end of the array. Once we reach the last element we can pick, we start again from the position next to the first selected element.
To illustrate, we start with the first element 80, skip 4 positions to 54, then to 67, and continue the pattern until the last possible element. Following this sequence, the first interleaved array will be: [ 80, 54, 67, 83, 43, 17, 42, 18, 13 ]. So the correct answer is a) [ 80, 54, 67, 83, 43, 17, 42, 18, 13 ].
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Final answer:
The correct option is c) [ 80, 67, 54, 83, 43, 17, 42, 18, 13 ].
Explanation:
To create an interleaved array with a gap of 4, we start with the first element of the original array and then select every 4th element (considering a wrap-around at the end of the array). The first element is 80. The next element, proceeding with a gap of four, would be 67 (from 80, skip three elements [43, 18, 83]). Continuing in this fashion, the pattern is: 80 to 67 (skip three: [43, 18, 83]), to 54 (skip three: [83, 43, 18]), to 83, to 43, to 17 (skip three: [54, 67, 13]), to 42 (skip three: [13, 80, 43]), to 18, and finally to 13. The resulting interleaved array with a gap of four yields the sequence 80, 67, 54, 83, 43, 17, 42, 18, 13, matching option c).
