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According to a recent study, [tex]15\%[/tex] of adults who take a certain medication experience side effects. To further investigate this finding, a researcher selects a separate random sample of 150 adults, of which 32 experience side effects. The researcher would like to determine if there is convincing statistical evidence that the true proportion of adults who would experience side effects from this medication is greater than 0.15 using a significance level of [tex]\alpha=0.05[/tex].

Complete the "State" and "Plan" steps. Which statements are true? Check all that apply.

- [tex]H_0: p=0.15[/tex]
- [tex]H_a: p\ \textgreater \ 0.15[/tex]
- The random condition is met.
- The [tex]10\%[/tex] condition is met.
- The large counts condition is met.
- The test is a [tex]z[/tex]-test for one proportion.

Answer :

Sure! Let's go through the problem and determine which statements are true regarding the hypothesis test.

State the Hypotheses:

1. Null Hypothesis ([tex]\(H_0\)[/tex]): The null hypothesis is that the true proportion of adults who experience side effects is equal to 0.15.
[tex]\[
H_0: p = 0.15
\][/tex]

2. Alternative Hypothesis ([tex]\(H_a\)[/tex]): The alternative hypothesis is what the researcher wants to prove, which is that the true proportion of adults who experience side effects is greater than 0.15.
[tex]\[
H_a: p > 0.15
\][/tex]

This is a one-tail test because we are checking if the proportion is greater than 0.15.

Plan the Test:

To conduct this hypothesis test, we need to ensure certain conditions are met:

1. Random Condition: This condition requires that the sample must be randomly selected. According to the problem, a separate random sample of adults was selected, so this condition is met.

2. 10% Condition: This condition states that the sample size should be no more than 10% of the population to ensure independence. Assuming the population of adults taking this medication is at least 1500, the sample size of 150 is indeed less than 10% of this assumed population (0.10 * 1500 = 1500), so this condition is met.

3. Large Counts Condition: This condition ensures that the sample is large enough for the normal approximation to be valid, requiring:
[tex]\[
np_0 \geq 10 \quad \text{and} \quad n(1-p_0) \geq 10
\][/tex]
For [tex]\(p_0 = 0.15\)[/tex] and [tex]\(n = 150\)[/tex]:
[tex]\[
150 \times 0.15 = 22.5 \quad (\text{which is } \geq 10)
\][/tex]
[tex]\[
150 \times (1-0.15) = 127.5 \quad (\text{which is } \geq 10)
\][/tex]
Both calculations satisfy the large counts condition.

4. Test Type: The test we use when checking a proportion with the conditions being met is a [tex]\(z\)[/tex]-test for one proportion.

Conclusion:

Based on the steps and conditions above, the true statements about this hypothesis test are:

- [tex]\(H_0: p = 0.15\)[/tex]
- The random condition is met.
- The 10% condition is met.
- The large counts condition is met.
- The test is a [tex]\(z\)[/tex]-test for one proportion.

The [tex]\(H_a: p < 0.15\)[/tex] statement is false because our alternative hypothesis is that the proportion is greater than 0.15, not less.

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