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What is the domain of the function [tex]h[/tex]?

[tex]h(x) = \sqrt{x-7} + 5[/tex]

A. [tex]x \leq 5[/tex]
B. [tex]x \geq 7[/tex]
C. [tex]x \leq -7[/tex]
D. [tex]x \geq 5[/tex]

Answer :

To determine the domain of the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex], we need to ensure that the expression inside the square root is non-negative. This is because the square root function is only defined for non-negative numbers. Let's go through the steps:

1. Expression Inside the Square Root: The expression under the square root is [tex]\( x - 7 \)[/tex].

2. Set the Expression to be Non-negative: We need [tex]\( x - 7 \geq 0 \)[/tex].

3. Solve the Inequality: To find when [tex]\( x - 7 \geq 0 \)[/tex], solve the inequality:
[tex]\[
x - 7 \geq 0
\][/tex]
Add 7 to both sides to get:
[tex]\[
x \geq 7
\][/tex]

4. Conclusion: The domain of the function [tex]\( h(x) = \sqrt{x - 7} + 5 \)[/tex] is all values of [tex]\( x \)[/tex] for which [tex]\( x \geq 7 \)[/tex].

Therefore, the correct answer is B. [tex]\( x \geq 7 \)[/tex].

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