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Calculate the sum:

\[ 8 \frac{1}{5} + 6 \frac{2}{3} = \]

A. \[ 14 \frac{1}{4} \]

B. \[ 14 \frac{3}{8} \]

C. \[ 15 \frac{13}{15} \]

D. \[ 14 \frac{13}{15} \]

Answer :

To solve the addition of mixed numbers [tex]\(8 \frac{1}{5} + 6 \frac{2}{3}\)[/tex], follow these steps:

1. Convert the mixed numbers to improper fractions:
- For [tex]\(8 \frac{1}{5}\)[/tex]: Multiply the whole number 8 by the denominator 5 and add the numerator 1, resulting in the improper fraction [tex]\(\frac{41}{5}\)[/tex].
- For [tex]\(6 \frac{2}{3}\)[/tex]: Multiply the whole number 6 by the denominator 3 and add the numerator 2, resulting in the improper fraction [tex]\(\frac{20}{3}\)[/tex].

2. Find a common denominator:
- The denominators are 5 and 3. The least common multiple (LCM) is 15.

3. Adjust the improper fractions to have the common denominator of 15:
- For [tex]\(\frac{41}{5}\)[/tex]: Multiply both the numerator and the denominator by 3 to get [tex]\(\frac{123}{15}\)[/tex].
- For [tex]\(\frac{20}{3}\)[/tex]: Multiply both the numerator and the denominator by 5 to get [tex]\(\frac{100}{15}\)[/tex].

4. Add the adjusted fractions:
- Add [tex]\(\frac{123}{15} + \frac{100}{15} = \frac{223}{15}\)[/tex].

5. Convert the improper fraction to a mixed number:
- Divide the numerator 223 by the denominator 15. The quotient is 14 with a remainder of 13.
- Therefore, [tex]\(\frac{223}{15}\)[/tex] converts to the mixed number [tex]\(14 \frac{13}{15}\)[/tex].

Thus, the sum of [tex]\(8 \frac{1}{5} + 6 \frac{2}{3}\)[/tex] is [tex]\(14 \frac{13}{15}\)[/tex].

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