High School

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Which expression is equal to [tex]$(3x-5)(2x-7)$[/tex]?

A. [tex]$6x^2 - 31x + 35$[/tex]
B. [tex][tex]$5x^2 - 21x + 12$[/tex][/tex]
C. [tex]$6x^2 + 31x - 35$[/tex]
D. [tex]$6x^2 - 31x - 12$[/tex]

Answer :

To find the expression that is equal to [tex]\((3x - 5)(2x - 7)\)[/tex], we need to expand the given product [tex]\((3x - 5)(2x - 7)\)[/tex].

Let's break it down step-by-step:

1. Expand the binomials:
[tex]\[
(3x - 5)(2x - 7) = 3x \cdot 2x + 3x \cdot (-7) + (-5) \cdot 2x + (-5) \cdot (-7)
\][/tex]

2. Multiply the terms:
[tex]\[
= 3x \cdot 2x + 3x \cdot (-7) + (-5) \cdot 2x + (-5) \cdot (-7)
\][/tex]
[tex]\[
= 6x^2 + (-21x) + (-10x) + 35
\][/tex]

3. Combine the like terms (the [tex]\(x\)[/tex] terms):
[tex]\[
= 6x^2 - 21x - 10x + 35
\][/tex]
[tex]\[
= 6x^2 - 31x + 35
\][/tex]

So the expression that matches the expanded product of [tex]\((3x - 5)(2x - 7)\)[/tex] is:
[tex]\[
6x^2 - 31x + 35
\][/tex]

Therefore, the correct answer is:
[tex]\[ 6x^2 - 31x + 35 \][/tex]

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