We appreciate your visit to How many grams of K₂CrO₄ m w 194 2 g mol are needed to prepare 250 0 mL of a 0 50 M solution in. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
To prepare a 250.0 mL solution of 0.50 M K₂CrO₄, 24.3 grams of K₂CrO₄ are needed, which corresponds to answer option A. Therefore the correct answer is A) 24.3 g.
Explanation:
The question is asking for the mass of K₂CrO₄ (potassium chromate) needed to prepare a 250.0 mL solution with a molarity of 0.50 M. To calculate this, use the molarity equation, M = moles/L, where M is molarity, moles is the amount of substance in moles, and L is the volume of solution in liters.
Hence, moles = M × L. After calculating the number of moles required, the mass of K₂CrO₄ can be determined by multiplying the number of moles by the molar mass (194.2 g/mol).
First, convert 250.0 mL to liters: 250.0 mL = 0.2500 L. Next, calculate the moles needed: moles = 0.50 M × 0.2500 L = 0.1250 mol. Finally, find the mass: mass = 0.1250 mol × 194.2 g/mol = 24.3 g.
Thus, the correct answer is: A) 24.3 g.
Thanks for taking the time to read How many grams of K₂CrO₄ m w 194 2 g mol are needed to prepare 250 0 mL of a 0 50 M solution in. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
