We appreciate your visit to At the Fisher Farm the weights of zucchini squash are normally distributed Which standardized weight represents the 5th percentile A 1 64 B 1 28. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The standardized weight representing the 5th percentile in a normally distributed set of data is a Z-score of -1.64, which corresponds to option A.
Explanation:
The standardized weight that represents the 5th percentile for a normally distributed set of data can be found by looking at a standard normal distribution table or using a Z-score calculator.
The 5th percentile falls in the left tail of the normal distribution. This is equivalent to a Z-score that marks the point below which 5% of the data fall.
The correct Z-score that corresponds to the 5th percentile of a normal distribution is -1.64.
Therefore, the answer to your question is A. -1.64.
This Z-score indicates that the weight of the zucchini squash that corresponds to the 5th percentile is 1.64 standard deviations below the mean weight of the zucchini squash at Fisher Farm.
Thanks for taking the time to read At the Fisher Farm the weights of zucchini squash are normally distributed Which standardized weight represents the 5th percentile A 1 64 B 1 28. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
