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A sample of nitrogen gas occupies a volume of 9.80 L at 52.0 °C and 0.430 atm. If it is desired to increase the volume of the gas sample to 11.9 L while decreasing its pressure to 0.329 atm, what must the temperature of the gas sample be at the new volume and pressure?

A. 45.6 °C
B. 37.9 °C
C. 49.3 °C
D. 52.8 °C

Answer :

Final answer:

The question can be solved using the combined gas law. Convert all temperatures to the Kelvin scale first, apply the formula, and, finally, convert the new temperature back to Celsius.

Explanation:

To solve this problem, you will need to use the combined gas law, which states that p1v1/t1 = p2v2/t2, where p represents the pressure of the gas, v the volume, and t the temperature. The numbers 1 and 2 specify initial and final states of the system.

To modify this law for your problem, you should first convert all temperatures to the Kelvin scale, as gas laws require absolute temperature measurements. To convert Celsius to Kelvin, use the formula: K = °C + 273.15. Therefore, your starting temperature of 52.0°C becomes 325.15 K.

Applying the combined gas law, we have: (0.430 atm * 9.80 L) / 325.15 K = (0.329 atm * 11.9 L) / t2

Solving this equation gives the temperature at the new condition, which you convert back to °C for your final answer. From the provided options, the answer will be among a. 45.6 °C b. 37.9 °C c. 49.3 °C d. 52.8 °C.

Learn more about Combined Gas Law here:

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