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Answer :
Final answer:
The IQ of an 8-year old who responded with the proficiency of a 10-year-old on the Stanford-Binet test would be 125 (calculated as (10/8) * 100). This is because the Stanford-Binet test calculates IQ by comparing individuals' mental age to their chronological age.
Explanation:
The concept under discussion is related to the scoring of IQ (Intelligence Quotient) which measures an individual's mental agility relative to their age. The Stanford-Binet is a type of IQ test that adheres to a bell curve, with the average intelligence score set at 100. To calculate one's IQ using the Stanford-Binet system, psychologists compare the mental age (the age level at which a person performs intellectually) to the individual's real, chronological age.
Given this scoring method and the question details, an 8-year-old who demonstrates the proficiency of an average 10-year-old would possess an IQ over 100. This is calculated as (mental age/chronological age) * 100, so in this case, (10/8) * 100 = 125.
It's worth noting that such a result would place the child in the high average classification of intelligence, as scores between 120-129 are typically considered to be 'superior' intelligence. Overall, the correct answer is d. 125.
Learn more about Intelligence Quotient (IQ) here:
https://brainly.com/question/34285268
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