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Answer :
Final answer:
The student's questions concern an RLC circuit, specifically regarding the current from the AC supply, the voltage on the capacitor, and the value of the capacitance. Techniques used include calculations based on the power factor, RMS values, and the relationship between capacitive reactance and the voltage across the capacitor.
Explanation:
The student is asking for assistance with calculations related to an RLC circuit with a coil and capacitor in series connected to an AC supply. The questions revolve around determining the current drawn from the supply, the voltage drop across the capacitor, and the capacitance of the capacitor.
For the current drawn from the supply, we can use the fact that the power factor is given (0.9063) and the RMS value of the current is given (14.4 A). The RMS value of the voltage is also given (234.65 V). The apparent power (S) can be calculated using the equation S = Vrms * Irms. To determine the real power (P), we use the equation P = S * Power Factor. Finally, the RMS current from the supply (Irms_supply) can be found using P = Vrms * Irms_supply * Power Factor, solving for Irms_supply.
To calculate the voltage drop across the capacitor, we must understand that in a series circuit, the sum of the voltage drops across each component equals the total voltage supplied. Since the voltage drop across the inductor is given, and the voltage drop across the resistor is not mentioned (assuming ideal components), and the supply voltage is known, the voltage drop across the capacitor can be found by the difference.
For the capacitance, we'll use the relationship between capacitive reactance (Xc = 1 / (2πfC)) and the rms voltage across the capacitor (Vc_rms). Once Vc_rms is known, we can solve for the capacitive reactance (Xc = Vc_rms / Irms) and from there determine the capacitance (C).
Learn more about RLC Circuit Calculations here:
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