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Answer :
To solve the division problem [tex]\(181 \div 17\)[/tex], we are going to find both the quotient and the remainder.
Step 1: Find the Quotient
- Divide 181 by 17. We need to determine how many times 17 can fit into 181 without exceeding it.
- Start by approximating:
- 17 goes into 18 once (since 17 is less than 18).
- Now multiply 17 by 10 (since we are looking at the tens place) to get 170.
- 17 fits into 181 a total of 10 times (since 170 is close to 181 but doesn't exceed it).
So, the quotient is 10.
Step 2: Calculate the Remainder
- Multiply the quotient by the divisor: [tex]\(10 \times 17 = 170\)[/tex].
- Subtract this result from the original dividend to find the remainder: [tex]\(181 - 170 = 11\)[/tex].
So, the remainder is 11.
Final Result:
When 181 is divided by 17, the quotient is 10 and the remainder is 11. Therefore, the answer is:
Quotient = 10
Remainder = 11
Step 1: Find the Quotient
- Divide 181 by 17. We need to determine how many times 17 can fit into 181 without exceeding it.
- Start by approximating:
- 17 goes into 18 once (since 17 is less than 18).
- Now multiply 17 by 10 (since we are looking at the tens place) to get 170.
- 17 fits into 181 a total of 10 times (since 170 is close to 181 but doesn't exceed it).
So, the quotient is 10.
Step 2: Calculate the Remainder
- Multiply the quotient by the divisor: [tex]\(10 \times 17 = 170\)[/tex].
- Subtract this result from the original dividend to find the remainder: [tex]\(181 - 170 = 11\)[/tex].
So, the remainder is 11.
Final Result:
When 181 is divided by 17, the quotient is 10 and the remainder is 11. Therefore, the answer is:
Quotient = 10
Remainder = 11
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