Find the following:

(i) $\frac{6}{10}$ of 90

(ii) $\frac{7}{11}$ of 165

(iii) $\frac{5}{12}$ of 3 years

(iv) $\frac{7}{15}$ of 2 kg

Question

High School

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Answer :

LucasMatthewHarris LucasMatthewHarris · Answer 1 · 2025-05-03T17:22:39-04:00

Let's solve each part step-by-step:

(i) [tex]\frac{6}{10}[/tex] of 90:

To find [tex]\frac{6}{10}[/tex] of 90, multiply 90 by [tex]\frac{6}{10}[/tex]:

[tex]\frac{6}{10} \times 90 = \frac{6 \times 90}{10} = \frac{540}{10} = 54[/tex]

So, [tex]\frac{6}{10}[/tex] of 90 is 54.

(ii) [tex]\frac{7}{11}[/tex] of 165:

To find [tex]\frac{7}{11}[/tex] of 165, multiply 165 by [tex]\frac{7}{11}[/tex]:

[tex]\frac{7}{11} \times 165 = \frac{7 \times 165}{11} = \frac{1155}{11} = 105[/tex]

So, [tex]\frac{7}{11}[/tex] of 165 is 105.

(iii) [tex]\frac{5}{12}[/tex] of 3 years:

First, consider that 1 year has 12 months. Therefore, 3 years is:

[tex]3 \times 12 = 36 \text{ months}[/tex]

Now, find [tex]\frac{5}{12}[/tex] of 36 months:

[tex]\frac{5}{12} \times 36 = \frac{5 \times 36}{12} = \frac{180}{12} = 15[/tex]

So, [tex]\frac{5}{12}[/tex] of 3 years is 15 months.

(iv) [tex]\frac{7}{15}[/tex] of 2 kg:

To find [tex]\frac{7}{15}[/tex] of 2 kg, multiply 2 by [tex]\frac{7}{15}[/tex]:

[tex]\frac{7}{15} \times 2 = \frac{7 \times 2}{15} = \frac{14}{15} \approx 0.933 ext{ kg}[/tex]

So, [tex]\frac{7}{15}[/tex] of 2 kg is approximately 0.933 kg.