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Answer :
The moment of inertia of the see-saw relative to the fulcrum is calculated using the formula for a uniform rod pivoted at the center, resulting in a moment of inertia of 204.75 kg-m².
To calculate the moment of inertia of a see-saw not including the people, we would use the parallel axis theorem. For a uniform rod pivoted at the center, the moment of inertia is given by I = 1/12 * m * L2, where m is the mass of the rod (the see-saw), and L is its length. As the see-saw is uniform and has a mass (m) of 273 kg and length (L) of 3 meters, we can substitute those values into the formula.
The calculation would be I = 1/12 * 273kg * (3m)2 = 1/12 * 273kg * 9m2 = 273kg * 0.75m2 = 204.75 kg \\(cdot\\) m2
Thus, the moment of inertia of the see-saw relative to the fulcrum is 204.75 kg \\(cdot\\) m2.
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