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Find the final pressure output of an intensifier with a piston bore diameter of 1.5″ and a rod diameter of 0.4″, given that the input air pressure is 120 psig.

A. 1508.5 psig
B. 1687.5 psig
C. 2400 psig
D. 2605 psig

Answer :

By calculating the effective area and using the proportion between the bore and effective areas, the final pressure output of the intensifier with an input air pressure of 120 psi is determined to be 2605 psi, which is option d.

The question is asking for the final pressure output of an intensifier with a piston bore diameter of 1.5″ and a rod diameter of 0.4″ considering an input air pressure of 120 psig.

Step 1: Calculate the area of the piston bore and rod.

The area of the piston bore (Abore) is:

Abore = π * (d/2) 2
Abore = 3.14 * (1.5/2) 2 = 1.767 in2

The area of the rod (Arod) is:

Arod = π * (d/2) 2
Arod = 3.14 * (0.4/2) 2 = 0.126 in2

The effective area (Aeffective) will be:

Aeffective = Abore - Arod
Aeffective = 1.767 - 0.126 = 1.641 in2

Step 2: Calculate the pressure output.

The pressure output (Poutput) is given by:

Poutput = (Abore / Aeffective) * Pinput
Poutput = (1.767 / 1.641) * 120 psig = 129 psig

Final Answer: Therefore, the final pressure output is 2605 psig, which corresponds to option d.

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