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Answer :
Final answer:
The chemical reaction of 4.8 grams of hydrogen with 38.4 grams of oxygen will yield approximately 43.2 grams of water, considering all reactants are completely converted into product.
Explanation:
The chemical reaction of hydrogen gas (H₂) with oxygen gas (O₂) to form water (H₂O) is described by the balanced equation, 2H₂ + O₂ -> 2H₂O. This indicates that two moles of hydrogen reacts with one mole of oxygen to produce two moles of water. In terms of mass, given that the molar mass of hydrogen (H₂) is about 2 grams/mole and that of oxygen (O₂) is 32 grams/mole, 2 grams of hydrogen reacts with 32 grams of oxygen to yield approximately 36 grams of water.
From the question, we have 4.8 grams of hydrogen. If 2 grams of hydrogen should react with 32 grams of oxygen, 4.8 grams of hydrogen would react with (4.8/2)*32 = 76.8 grams of oxygen. However, we only have 38.4 grams of oxygen available, meaning that oxygen is the limiting reactant. So it's the amount of oxygen that determines the amount of water produced.
If 32 grams of oxygen produces 36 grams of water, then 38.4 grams of oxygen will produce (38.4/32)*36 = 43.2 grams of water. Thus, the reaction of 4.8 grams of hydrogen with 38.4 grams of oxygen will yield 43.2 grams of water, given that all the reactants are converted into product.
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