High School

We appreciate your visit to A block of mass 4 3 kg sliding on a horizontal plane is released with a velocity of 3 6 m s The block slides. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A block of mass 4.3 kg, sliding on a horizontal plane, is released with a velocity of 3.6 m/s. The block slides and stops at a distance of 2 m beyond the point where it was released. How far would the block have slid if its initial velocity were quadrupled?

A) 4 m
B) 8 m
C) 16 m
D) 2 m

Answer :

Final answer:

If the initial velocity of the block is quadrupled, it would slide 8 meters.

Explanation:

The distance traveled by an object depends on its initial velocity and the forces acting on it. In this case, the block of mass 4.3 kg is initially sliding with a velocity of 3.6 m/s and comes to rest at a distance of 2 m. To find the distance the block would have slid if its initial velocity were quadrupled, we can use the concept of energy conservation.

When the block comes to rest, all of its initial kinetic energy is converted into potential energy. By doubling the initial velocity, the block will have four times the initial kinetic energy. Therefore, the distance it will slide before coming to rest will quadruple as well.

So if the initial velocity were quadrupled, the block would slide 4 times the distance, which is 2 m * 4 = 8 m.

Thanks for taking the time to read A block of mass 4 3 kg sliding on a horizontal plane is released with a velocity of 3 6 m s The block slides. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada