High School

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Suppose [tex]$y$[/tex] varies directly as [tex]$x$[/tex]. If [tex][tex]$y=7$[/tex][/tex] when [tex]$x=28$[/tex], what is the value of [tex]$x$[/tex] when [tex][tex]$y=3$[/tex][/tex]?

A. 7
B. 9
C. 12
D. 16

Answer :

Certainly! In this problem, we know that [tex]\( y \)[/tex] varies directly as [tex]\( x \)[/tex], meaning there's a direct relationship between them. This can be written as:

[tex]\[ y = kx \][/tex]

where [tex]\( k \)[/tex] is the constant of proportionality.

### Step 1: Find the Constant of Proportionality

We are given that [tex]\( y = 7 \)[/tex] when [tex]\( x = 28 \)[/tex]. We can use this to find the value of [tex]\( k \)[/tex]:

[tex]\[ 7 = k \times 28 \][/tex]

To find [tex]\( k \)[/tex], divide both sides by 28:

[tex]\[ k = \frac{7}{28} \][/tex]

So, [tex]\( k = 0.25 \)[/tex].

### Step 2: Find [tex]\( x \)[/tex] When [tex]\( y = 3 \)[/tex]

Now we need to find the value of [tex]\( x \)[/tex] when [tex]\( y = 3 \)[/tex]. We will use the same proportional relationship:

[tex]\[ 3 = 0.25 \times x \][/tex]

To find [tex]\( x \)[/tex], divide both sides by 0.25:

[tex]\[ x = \frac{3}{0.25} \][/tex]

Calculating this gives:

[tex]\[ x = 12 \][/tex]

Therefore, the value of [tex]\( x \)[/tex] when [tex]\( y = 3 \)[/tex] is [tex]\( 12 \)[/tex].

The correct answer is:
c. 12

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