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A 25.0 mL sample of a saturated [tex]\text{Ca(OH)}_2[/tex] solution is titrated with 0.028 M HCl, and the equivalence point is reached after 38.1 mL of titrant are dispensed. Based on this data, what is the concentration (M) of the hydroxide ion?

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Answer :

The concentration (M) of the hydroxide ion when 25ml of saturated Ca(OH)₂ is titrated with 0.028 ml of HCl is 0.054 M.

The concentration of the hydroxide ions can be calculated using the following formula:

[OH⁻] = ([tex]V_{B}[/tex] × [tex]M_{B}[/tex])/ ([tex]V_{S}[/tex] × n)

where [tex]V_{B}[/tex] is the volume of HCl used, [tex]M_{B}[/tex] is the molarity of HCl, [tex]V_{S}[/tex] is the volume of Ca(OH)₂ solution used and n is the number of OH⁻ ions per molecule of Ca(OH)₂ which is 2.

Here, [.] denotes the concentration of an entitled ion or molecule.

The concentration of a chemical species, specifically a solute in a solution, is measured by its molarity. It is described as the quantity of solute in one liter of solution, expressed in moles. The letter M stands for molarity.

After substituting the values provided in the question, we get:

[OH⁻] = (38.1 ml × 0.028 M) / (25 ml × 2)

[OH⁻] = 0.054 M

Therefore, the concentration of hydroxide ion in the saturated Ca(OH)2 solution is 0.054 M.

To know more about concentration of ions, refer:

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