We appreciate your visit to The table below shows the data for a car stopping on a wet road What is the approximate stopping distance for a car traveling at. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To find the approximate stopping distance for a car traveling at 35 mph on a wet road, we use the formula provided:
[tex]\[ d = \frac{2.15 \times v^2}{64.4 \times f} \][/tex]
Where:
- [tex]\( d \)[/tex] is the stopping distance in feet.
- [tex]\( v \)[/tex] is the velocity of the car in mph.
- [tex]\( f \)[/tex] is the friction coefficient (which is often assumed to be 0.7 for wet roads).
Let's go through the solution step-by-step:
1. Identify the given values:
- Velocity ([tex]\( v \)[/tex]) = 35 mph
- Friction coefficient ([tex]\( f \)[/tex]) = 0.7
2. Understand the formula:
- This formula calculates the stopping distance using a combination of velocity ([tex]\( v \)[/tex]) and the friction coefficient ([tex]\( f \)[/tex]). The term [tex]\( 2.15 \times v^2 \)[/tex] represents a factor based on speed, while the denominator [tex]\( 64.4 \times f \)[/tex] accounts for road conditions.
3. Substitute the values into the formula:
[tex]\[
d = \frac{2.15 \times (35)^2}{64.4 \times 0.7}
\][/tex]
4. Calculate the stopping distance:
- First, calculate [tex]\( v^2 \)[/tex]: [tex]\( 35 \times 35 = 1225 \)[/tex]
- Then, multiply by 2.15: [tex]\( 2.15 \times 1225 = 2637.75 \)[/tex]
- Calculate the denominator: [tex]\( 64.4 \times 0.7 = 45.08 \)[/tex]
- Divide the results to find the stopping distance:
[tex]\[
d = \frac{2637.75}{45.08} \approx 58.42
\][/tex]
The approximate stopping distance for the car traveling at 35 mph on a wet road is approximately 58.4 feet.
[tex]\[ d = \frac{2.15 \times v^2}{64.4 \times f} \][/tex]
Where:
- [tex]\( d \)[/tex] is the stopping distance in feet.
- [tex]\( v \)[/tex] is the velocity of the car in mph.
- [tex]\( f \)[/tex] is the friction coefficient (which is often assumed to be 0.7 for wet roads).
Let's go through the solution step-by-step:
1. Identify the given values:
- Velocity ([tex]\( v \)[/tex]) = 35 mph
- Friction coefficient ([tex]\( f \)[/tex]) = 0.7
2. Understand the formula:
- This formula calculates the stopping distance using a combination of velocity ([tex]\( v \)[/tex]) and the friction coefficient ([tex]\( f \)[/tex]). The term [tex]\( 2.15 \times v^2 \)[/tex] represents a factor based on speed, while the denominator [tex]\( 64.4 \times f \)[/tex] accounts for road conditions.
3. Substitute the values into the formula:
[tex]\[
d = \frac{2.15 \times (35)^2}{64.4 \times 0.7}
\][/tex]
4. Calculate the stopping distance:
- First, calculate [tex]\( v^2 \)[/tex]: [tex]\( 35 \times 35 = 1225 \)[/tex]
- Then, multiply by 2.15: [tex]\( 2.15 \times 1225 = 2637.75 \)[/tex]
- Calculate the denominator: [tex]\( 64.4 \times 0.7 = 45.08 \)[/tex]
- Divide the results to find the stopping distance:
[tex]\[
d = \frac{2637.75}{45.08} \approx 58.42
\][/tex]
The approximate stopping distance for the car traveling at 35 mph on a wet road is approximately 58.4 feet.
Thanks for taking the time to read The table below shows the data for a car stopping on a wet road What is the approximate stopping distance for a car traveling at. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
