Give a complete electron configuration, an abbreviated electron configuration, an abbreviated orbital diagram, and state whether the element (or ion) would be diamagnetic or paramagnetic for Fe$^{2+}$.

Question

17-03-2025
Chemistry

High School

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Give a complete electron configuration, an abbreviated electron configuration, an abbreviated orbital diagram, and state whether the element (or ion) would be diamagnetic or paramagnetic for Fe$^{2+}$.

Answer :

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BellaGordon BellaGordon · Answer 1 · 2024-03-13T01:35:09-04:00

The complete electron configuration of Fe²+ is 1s2 2s2 2p6 3s2 3p6 3d6. Fe²+ is diamagnetic. The abbreviated electron configuration is [Ar] 3d6. The abbreviated orbital diagram is shown as follows:
1s
2s
2p
3s
3p
4s
3d ↑ ↑ ↑ ↑ ↑ ↑
- Fe2+ is diamagnetic.

The electron configuration of Fe²+ can be determined by considering the number of electrons in the Fe²+ ion.

The atomic number of iron (Fe) is 26, meaning that a neutral iron atom has 26 electrons. However, Fe²+ is an ion with a charge of +2, indicating that it has lost 2 electrons.

To determine the electron configuration, we need to first fill the orbitals in order of increasing energy. The electron configuration for a neutral iron atom is:

1s2 2s2 2p6 3s2 3p6 4s2 3d6

Since Fe²+ has lost 2 electrons, the electron configuration for Fe²+ is:

1s2 2s2 2p6 3s2 3p6 3d6

The abbreviated electron configuration can be written as [Ar] 3d6. This indicates that the inner electron configuration is the same as that of the noble gas argon (Ar), which is the element before iron in the periodic table.

The orbital diagram for Fe2+ can be represented as follows:

1s
2s
2p
3s
3p
4s
3d ↑ ↑ ↑ ↑ ↑ ↑

In the orbital diagram, each orbital is represented by a box, and the electrons are represented by arrows. The arrows indicate the spin of the electrons, with ↑ representing an electron with a positive spin and ↓ representing an electron with a negative spin. Since Fe²+ has 6 electrons in the 3d orbital, all the 6 boxes in the 3d orbital are filled with arrows.

Now, let's determine whether Fe²+ is diamagnetic or paramagnetic.

Diamagnetic substances have all their electrons paired, while paramagnetic substances have unpaired electrons.

In the case of Fe²+, all the electrons in the 3d orbital are paired, meaning that there are no unpaired electrons. Therefore, Fe²+ is diamagnetic.

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Give a complete electron configuration, an abbreviated electron configuration, an abbreviated orbital diagram, and state whether the element (or ion) would be diamagnetic or paramagnetic for Fe\(^{2+}\).

Answer :

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