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Answer :
Final answer:
The student's question is a typical algebra problem to determine two people's ages based on their age difference and a comparison of their ages in the past. Solving the algebraic equation, we find that Morgan is currently 7 years old, and Leyton is 15 years old.
Explanation:
The question revolves around a basic age-related problem that can be solved using algebra. Leyton is 8 years older than Morgan. Three years ago, he was 3 times older than Morgan. To solve this, let's represent Morgan's current age as M, which means Leyton's current age is M + 8.
Three years ago, Morgan's age was M - 3 and Leyton's age was (M + 8) - 3. According to the given information, Leyton's age at that time was 3 times Morgan's age at that time. So, the equation based on this information is:
(M + 8 - 3) = 3 * (M - 3)
Solving for M gives us:
M + 5 = 3M - 9
2M = 14
M = 7
Now that we know Morgan's current age is 7 years, we can find Leyton's current age by adding 8 years, which gives us 15 years. So, Leyton is currently 15 years old, and Morgan is currently 7 years old.
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