High School

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The separation distance between two masses is 0.450 m. The objects have masses of 215 kg and 515 kg.

Find the net gravitational force exerted by these objects on a 44.0 kg object placed midway between them.

Answer :

The net gravitational force on a 44.0kg object placed midway between two masses of 215kg and 515kg is zero because the forces exerted by both masses are equal and opposite, thus cancelling each other out.

The question asks us to find the net gravitational force exerted on a 44.0kg object by two other objects with masses of 215kg and 515kg, which are placed symmetrically around it. To calculate the force of gravity between two objects, we use Newton's law of universal gravitation, which states that the gravitational force (">F ") between two masses (">m1 " and ">m2 ") is given by the equation

">F = G * (m1 * m2) / r2<"

(where ">G" is the gravitational constant and ">r" is the separation distance between the masses).

However, since the 44.0kg object is midway between the two other masses, the forces exerted by the 215kg and 515kg objects will be equal in magnitude but opposite in direction. Hence, they will cancel each other out, leading to a net gravitational force of zero on the 44.0kg object.

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