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Answer :
Final answer:
For 50 games in one evening, the number of games won would follow a Binomial Distribution with parameters (n, p), while the total score in the games could potentially follow a Normal Distribution with parameters (μ, σ), assuming certain conditions are met.
Explanation:
In the context of '50 games in one evening', the distribution for the number of games won would be a Binomial Distribution. The parameters would be (n, p) where 'n' is the number of games played, in this case 50, and 'p' is the probability of winning a game.
On the other hand, the distribution for the total score in the games could potentially fall into a Normal Distribution if the sum of a large number of random variables is involved. The parameters here would be (μ, σ) where 'μ' is the mean score across all games and 'σ' is the standard deviation.
However, please note, these statements presume that the probability of winning a game remains constant across all games and the scores from each game is independent and identically distributed, which may not always be the case.
Learn more about Probability Distributions here:
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