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A 2.00 × 10⁻¹ m glucose solution is made by dissolving glucose in 100.0 kg of water. What is the amount of glucose in moles?

a) 0.1 mol
b) 1 mol
c) 5 mol
d) 10 mol

Answer :

Final answer:

The number of moles of glucose in a 2.00×10⁻¹ m solution with 100.0 kg of water as the solvent is calculated using molality as 10 mol. Option d is correct.

Explanation:

The molality (m) of a solution is referred to as the number of moles of solute per kilogram of solvent, hence, m = mol solute/kg solvent. Given that the molality of the solution is 0.1 m, we can calculate the moles of glucose.

Using the formula:

  • m = mol solute / kg solvent

We know that:

  • m = 0.1 m
  • kg solvent = 100.0 kg

We simply multiply the molality by the mass of the solvent to find the moles of solute:

0.1 mol/kg × 100.0 kg = 10 mol

Hence, the correct answer is 10 mol of glucose in the solution which corresponds to option d.

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