High School

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A toy rocket is launched vertically upward from a 12-foot platform with an initial velocity of 128 feet per second. Its height, \( h \), at time \( t \) seconds after launch is given by the equation:

\[ h(t) = -16t^2 + 128t + 12. \]

How long will it take the rocket to reach the ground?

Answer :

Final answer:

To determine when the toy rocket reaches the ground, solve the quadratic equation h(t) = -16t^2 + 128t + 12 by finding the positive root, which gives 8.124 seconds as the time for the rocket to hit the ground.

Explanation:

To find out how long it will take the toy rocket to reach the ground, we need to solve the equation h(t) = -16t2 + 128t + 12 for the time t when the height h(t) is zero, as that represents the ground level.

Set the equation equal to zero and factor or use the quadratic formula:

  • 0 = -16t2 + 128t + 12

Solve for t:

  • t = (-b ± √(b2 - 4ac)) / (2a)
  • t = (-128 ± √(1282 - 4(-16)(12)) / (-32)
  • t = (-128 ± √(16384 + 768)) / (-32)
  • t = (-128 ± √(17152)) / (-32)
  • t = (-128 ± 130.969) / (-32)
  • t = (128 - 130.969) / (-32) or t = (128 + 130.969) / (-32)
  • t = -0.093 or t = 8.124

Because time cannot be negative for the scenario after launch, the rocket will hit the ground 8.124 seconds after it is launched.

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