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When the following code has finished running. what is the value of x?

x = _____

int x=100;

int * y = &x;

int * z = &x

x = 50;

*y = 300;

*z = 50;

Answer :

The value of x is 300. Let's break down the given code step by step: int x = 100; - This initializes the variable x with the value 100.

int *y = &x; - This declares a pointer variable y and assigns the memory address of x to it.

int *z = &x; - This declares another pointer variable z and assigns the memory address of x to it.

x = 50; - This assigns the value 50 to x.

*y = 300; - This dereferences the pointer y and assigns the value 300 to the variable it points to, which is x.

*z = 50; - This dereferences the pointer z and assigns the value 50 to the variable it points to, which is x.

After executing the code, the value of x is modified by both the assignment statements *y = 300; and *z = 50;. Therefore, the final value of x is 300.

Note: The initial assignment x = 50; does not affect the final value of x because it is overwritten by *y = 300;.

Learn more about pointers in C programming here: brainly.com/question/30905580

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