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Answer :
Final answer:
This approach entails defining C macros for flag values, and using bitwise operations to perform flag manipulation. Specific functions or code segments obtain, set, and clear a 3-bit flag within a byte without disturbing other bits.
Explanation:
The task at hand is to create a collection of C #defines for the different values a three-bit flag can have within a one-byte variable in C, as well as to write code to manipulate these flags without affecting other bits. To accomplish this, bitwise operations are used.
Define Possible Flag Values
#define FLAG_VALUE_0 (0x0 << 2) // 000
#define FLAG_VALUE_1 (0x1 << 2) // 001
#define FLAG_VALUE_2 (0x2 << 2) // 010
#define FLAG_VALUE_3 (0x3 << 2) // 011
#define FLAG_VALUE_4 (0x4 << 2) // 100
#define FLAG_VALUE_5 (0x5 << 2) // 101
#define FLAG_VALUE_6 (0x6 << 2) // 110
#define FLAG_VALUE_7 (0x7 << 2) // 111
Obtain the Value of the Flag
unsigned char getFlagValue(unsigned char flags) {
return (flags >> 2) & 0x07;
}
Set the Flag to a Value
void setFlagValue(unsigned char *flags, unsigned char value) {
*flags &= ~(0x07 << 2); // Clear the flag bits
*flags |= (value & 0x07) << 2; // Set the flag bits
}
Clear the Flag
void clearFlag(unsigned char *flags) {
*flags &= ~(0x07 << 2); // Clear the flag bits
}
To achieve this, first, the possible flag values are defined using #define. The value of the flag is obtained using a combination of the right shift operator (>>) and bitwise AND (&) to isolate the relevant bits. To set the flag to a given value, bitwise AND with a mask clears the bits, then bitwise OR (|) sets the new value. Clearing the flag simply involves clearing the relevant bits using a mask with bitwise AND.
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