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What is the de Broglie wavelength of an electron traveling at [tex]1.57 \times 10^5 \, \text{m/s}[/tex]?

Express your answer to three significant figures and include the appropriate units.

Answer :

Answer:16485 miles travel

Explanation:so if electon traveiling at so 1.57 x105 like i said think of it like math so use math for to include units m/s

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Rewritten by : Barada

Final answer:

The de Broglie wavelength of an electron traveling at 1.57×10^5 m/s is 4.63 × 10^-9 m.

Explanation:

The de Broglie wavelength of an electron traveling at a velocity of 1.57×105 m/s can be calculated using the equation λ = h / p, where λ is the de Broglie wavelength, h is Planck's constant (6.626 × 10-34 kg m²/s), and p is the momentum of the electron. Momentum can be calculated using the equation p = mv, where m is the mass of the electron and v is its velocity. The de Broglie wavelength of the electron can be found by substituting the values into the equation and solving for λ.

In this case, we need to know the mass of the electron, which is approximately 9.10938356 × 10-31 kg. Substituting these values into the equations, we have:

p = (9.10938356 × 10-31 kg) × (1.57×105 m/s) = 1.42906 × 10-25 kg m/s

λ = (6.626 × 10-34 kg m²/s) / (1.42906 × 10-25 kg m/s) = 4.63 × 10-9 m

Therefore, the de Broglie wavelength of the electron traveling at 1.57×105 m/s is 4.63 × 10-9 m.

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