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What is the domain of the function [tex]h(x) = \sqrt{x-7} + 5[/tex]?

A. [tex]x \leq 5[/tex]
B. [tex]x \geq 5[/tex]
C. [tex]x \geq 7[/tex]
D. [tex]x \leq -7[/tex]

Answer :

To find the domain of the function [tex]\( h(x) = \sqrt{x-7} + 5 \)[/tex], we need to determine the values of [tex]\( x \)[/tex] for which the expression is defined.

1. Understanding the Square Root: The square root function, [tex]\(\sqrt{x-7}\)[/tex], requires the expression inside the square root to be non-negative because the square root of a negative number is not defined in the set of real numbers.

2. Setting the Condition: To ensure that the expression inside the square root is non-negative, we set up the inequality:
[tex]\[
x - 7 \geq 0
\][/tex]

3. Solving the Inequality: Solving the inequality for [tex]\( x \)[/tex]:
[tex]\[
x \geq 7
\][/tex]

4. Conclusion: Thus, the domain of the function is all real numbers [tex]\( x \)[/tex] such that [tex]\( x \geq 7 \)[/tex].

Based on these steps, the correct answer is:

C. [tex]\( x \geq 7 \)[/tex]

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